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What Is CSIR NET? Routes, Eligibility and Marks for Maths

CSIR NET is a national test run by the National Testing Agency that qualifies science postgraduates for a research fellowship, a lecturing post or PhD admission. Maths has its own paper.

By Sunil Bansal, Founder · Updated 10 Oct 2026

A postgraduate student walks up the steps of a university exam building on a quiet morning.

Key takeaways

  • CSIR NET qualifies you for a JRF with a lecturing post, for a lecturing post with PhD admission, or for PhD admission only. Qualifying does not guarantee a fellowship.
  • You can apply while enrolled in a master's programme in any year, or with a four-year bachelor's degree at 75%. A three-year BSc alone does not qualify.
  • Compare your marks with your own category's JRF cut-off, not just the pass mark. The pass mark and the JRF cut-off are different lines.
  • Part C carries 95 of the 200 marks in the Mathematical Sciences paper. Attempt all 20 questions you are allowed there.
In this article
  1. 1What is CSIR NET, and what does a qualifying score give you?
  2. 2Who is eligible for CSIR NET in mathematics, and when can you apply?
  3. 3How is the Mathematical Sciences paper marked out of 200?
  4. 4Is the pass mark enough to win a JRF?
  5. 5How do you estimate whether your marks reach your category's JRF cut-off?
  6. 6How does SBTech Math prepare students for CSIR NET mathematics?
  7. 7Frequently asked questions

One CSIR NET score can lead to three different outcomes, and only one of them pays a stipend. The exam is the National Eligibility Test run for the Council of Scientific and Industrial Research (CSIR) jointly with the University Grants Commission (UGC). A maths student sits it in the Mathematical Sciences paper.

In June 2025, about 19% of the candidates who qualified across the five science subjects received a Junior Research Fellowship (JRF). That is our share, worked out from the results reported by Careers360. Most of the rest qualified for PhD admission, with or without eligibility for a lecturing post.

That gap decides how to prepare. The pass mark is low, the fellowship line is higher, and each moves on its own from one session to the next. This page explains what a qualifying score gives a maths student, who can sit the exam, how the paper turns into marks, and how to test your target against your own category's cut-off.

What is CSIR NET, and what does a qualifying score give you?

CSIR NET, the Joint CSIR-UGC National Eligibility Test, is conducted by the National Testing Agency (NTA) for CSIR. It decides whether Indian nationals are eligible for a Junior Research Fellowship (JRF), an Assistant Professor appointment, or PhD admission, in one of three combinations (about the Joint CSIR-UGC NET).

CategoryWhat you qualify forJRFAssistant ProfessorPhD admission
1JRF and Assistant ProfessorYesYesYes
2Assistant Professor and PhD admissionNoYesYes
3PhD admission onlyNoNoYes
Source: Information Bulletin, section 1.7, December 2026 session.

The rules that follow from the table:

  • A JRF holder is admitted to a PhD by interview.
  • For categories 2 and 3, the NET score counts for 70% of PhD admission and the university interview for 30%. The score is valid for one year for this purpose.
  • The Assistant Professor qualifying certificate has no end date.
  • As of the December 2026 bulletin, the JRF stipend is ₹37,000 a month for two years, plus a ₹20,000 yearly contingency grant. It rises to ₹42,000 a month from the third year as a Senior Research Fellow, after a progress review and if you are registered for a PhD (bulletin, section 1.8).

The outcomes are not evenly spread. For June 2025, Careers360 reported six qualifier groups across all five science subjects:

GroupCandidates
JRF with Assistant Professor984
JRF only9
JRF (Ministry of Earth Sciences)25
JRF (UGC scheme)1,866
Assistant Professor with PhD admission2,886
PhD admission only9,232

Our sums: the six groups add up to 15,002. The four JRF groups total 2,884, about 19%. Assistant Professor with PhD admission is 2,886, about 19%. PhD admission only is 9,232, about 62%. Maths-only counts are not in that report. For most qualifiers the exam is a route into a PhD, and the fellowship is the rarer outcome.

Who is eligible for CSIR NET in mathematics, and when can you apply?

As of the December 2026 bulletin, you can apply with a master's degree at 55% marks (50% for OBC non-creamy layer, SC, ST, PwD and third-gender candidates), or while enrolled in a master's programme in any year. Our eligibility guide covers each category in detail.

As of 10 October 2026, applications for the December 2026 session are open until 5 November 2026, and the exam is scheduled for 19, 22 and 27 December 2026 (bulletin, dates at a glance). Our application form guide walks through the steps, and our exam date page tracks the schedule.

The terms used in the table:

  • EWS: Economically Weaker Sections.
  • OBC-NCL: Other Backward Classes, non-creamy layer.
  • SC: Scheduled Caste.
  • ST: Scheduled Tribe.
  • PwD: persons with disabilities.
Your situationCan you apply?
Master's completed with 55% (General, EWS) or 50% (OBC-NCL, SC, ST, PwD, third gender)Yes, for all three categories
Pursuing a master's in any year, final-year result awaited, or result delayedYes, provisionally. You must finish with the required marks within two years of the NET result (one year if you qualify for PhD admission only)
Four-year (eight-semester) bachelor'sYes, with 75% aggregate (a 5% relaxation applies to SC, ST, OBC-NCL, PwD and EWS). You can qualify for JRF and PhD admission, but not for Assistant Professor
Three-year BSc onlyA three-year BSc alone is not among the qualifying degrees. You become eligible while pursuing a master's
Source: Information Bulletin, sections 2.1.1(a) to (i).

Age matters only for the JRF. You must be no more than 30 on the first day of the month in which the exam concludes. Up to five years' relaxation is available for OBC-NCL, SC, ST, PwD and third-gender candidates and for women, and also for research experience and armed forces service. The total relaxation cannot exceed five years. There is no upper age limit for Assistant Professor or PhD admission only (bulletin, section 2.1.2).

How is the Mathematical Sciences paper marked out of 200?

The Mathematical Sciences paper (subject code 704) has 120 questions, but you may attempt only 60, and it is marked out of 200. It is a three-hour computer-based test with no break between parts (bulletin, section 3.2).

Candidates sit at separate desks in a computer-based test hall, each facing a monitor.
The paper is one long, silent sitting at a screen, so stamina matters as much as speed.
PartQuestions in paperYou may attemptMarks per correct answerPenalty per wrong answerMaximum marks
A (general aptitude)201520.530
B (subject multiple-choice questions, MCQs)402530.7575
C (advanced)60204.75none95
Total12060200

Check: 15 × 2 = 30, 25 × 3 = 75 and 20 × 4.75 = 95, which total 200.

Two rules catch people out:

  • Answering more than the limit. If you answer more than 15, 25 or 20 questions in a part, only the first 15, 25 and 20 are marked. Extra answers earn nothing and use time you need elsewhere.
  • Part C works differently. A question can have one or more correct options, and you get credit only if you identify all of them. Wrong answers carry no penalty.

Parts A and B have one correct option per question, and a quarter of the marks is deducted for a wrong answer.

Is the pass mark enough to win a JRF?

No. The pass mark only makes you eligible to qualify, and your category's JRF cut-off decides the fellowship. For General candidates in Mathematical Sciences, the JRF cut-off sat 20 marks above the pass mark in June 2026 and about 41 marks above it in June 2025. There is no separate cut-off for Parts A, B and C. Cumulative marks decide the merit list, and the results committee sets how many candidates fall into each category. The minimum is 33% for General, EWS and OBC, and 25% for SC, ST and PwD (bulletin, section 11.3).

As of 10 October 2026, the latest published session is June 2026. Marks are our conversion: percentage × 200. The percentages are as reported on Adda247 (June 2026) and Careers360 (June 2025).

CategoryPass mark (of 200)JRF cut-off, June 2026JRF cut-off, June 2025
General (UR)6643.000% = 86.0053.375% = 106.75
EWS6637.625% = 75.2546.000% = 92.00
OBC6637.500% = 75.0043.375% = 86.75
SC5030.250% = 60.5035.375% = 70.75
ST5027.375% = 54.7530.750% = 61.50
PwD5025.250% = 50.5025.125% = 50.25

Cut-offs move between sessions. The General line fell by 20.75 marks between June 2025 and June 2026, and the SC line by 10.25. Our cut-off guide tracks them.

Two mistakes follow from this:

  • Aiming at the pass mark. A student who plans for 66 marks may qualify and still miss the fellowship line.
  • Neglecting Part C. Part C is the largest block of marks and has no penalty. Our recommendation is to attempt all 20 questions you are allowed there. Spend any time you save on Parts A and B on the Part C questions you can partly solve.

How do you estimate whether your marks reach your category's JRF cut-off?

Estimate your CSIR NET maths marks as 2 × A correct − 0.5 × A wrong + 3 × B correct − 0.75 × B wrong + 4.75 × C correct, then compare the total with your category's JRF cut-off in the table above. The formula is our working from the bulletin's marking scheme, not an official calculator. Run it on your last full-length mock paper.

A student checks a printed mock paper with a pencil at a tidy desk.
Scoring a full mock paper yourself turns the marking formula into a real estimate.
PartCorrectWrongMarksWorked example
A2c − 0.5w12 correct, 3 wrong: 24 − 1.5 = 22.5
B3c − 0.75w18 correct, 7 wrong: 54 − 5.25 = 48.75
C4.75c10 correct: 47.5
Total22.5 + 48.75 + 47.5 = 118.75

Read the total against these lines for your own category:

  1. Below your pass mark (66 or 50): fixing wrong answers in Parts A and B is the fastest gain.
  2. At or above the pass mark but below your category's JRF cut-off: you are in range to qualify, and the fellowship is not yet secured.
  3. At or above your category's JRF cut-off: the line moves, so as a rule of thumb, aim for 10 to 15 marks over the latest line. That is our rule of thumb, based on the moves of 10.25 and 20.75 marks between the last two sessions.

The worked example scores 118.75. A General candidate with that total would be 32.75 marks over the June 2026 line and 12 marks over the June 2025 line. It uses only 10 correct Part C answers, so Part C is where a stronger result would come from.

How does SBTech Math prepare students for CSIR NET mathematics?

SBTech Math offers live online classes and recorded courses for CSIR-NET, with PDF notes, assignments, previous-year-question discussion, mock tests and analytics. We also run a mathematics test series, including the Core Concept Diagnostic test series. SB Sir designs all of our test series and conceptual tests.

SB Sir teaches Pure Mathematics, Eshita Mam teaches Applied Mathematics, and Vivek Sir teaches Abstract Algebra and Real Analysis. Our app dashboard tracks course completion and test scores. Our courses are made for BSc students, MSc students, graduates and working learners.

You can start without paying. Our free mathematics study content includes TJK 9.0, demo classes, a PDF Drive, notes and previous-year questions.

As of October 2026, our paid options are:

  • CSIR-NET December 2026 Live Batch: ₹11,999 one-time, or three instalments of ₹3,999.67.
  • CSIR-NET and GATE Mathematics 2027: ₹15,999 one-time with access through 30 June 2027, or four instalments of ₹3,999.75.
  • Demo Plan: ₹999 for 10 days of access to the CSIR-NET and GATE Mathematics 2027 course.

To find out which option suits your stage, contact SBTech Math.

Find the right CSIR NET maths course for your stage

Contact SBTech Math to find out which live batch or course suits your stage.
Contact SBTech Math

Frequently asked questions

No. UGC NET is a separate National Testing Agency test for Assistant Professor and fellowship eligibility, with its own notice, subject list and syllabus. CSIR NET is called the Joint CSIR-UGC NET because it also offers UGC-scheme fellowships. Its Mathematical Sciences paper is the one this page describes.
You need 66 of 200 marks if you are General, EWS or OBC, and 50 of 200 if you are SC, ST or PwD. That makes you eligible to qualify. The JRF needs your category's higher cut-off.
Not with a three-year BSc alone. You can apply once you are enrolled in a master's programme, or with a four-year bachelor's degree at 75%. The four-year route leads to JRF or PhD admission only, not Assistant Professor.

For the December 2026 session, the application fee is ₹1,150 for General, ₹600 for General-EWS and OBC-NCL, and ₹325 for SC, ST, PwD and third-gender candidates. A late fee of ₹500 applies after the deadline. Fees can change by session (bulletin, dates and fees at a glance).

Sources

  1. 1.Information Bulletin, Joint CSIR-UGC NET December 2026 (sections 1.7, 1.8, 2.1, 3.2, 11.3, and the dates and fees table), National Testing Agency
  2. 2.About Joint CSIR-UGC, National Testing Agency
  3. 3.CSIR NET cut-off 2025 and June 2025 qualifier counts, Careers360
  4. 4.CSIR NET cut-off 2026 (June session), Adda247

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